are Siblings ordered?

Pedram Nimreezi mc at majorcomputing.com
Tue Oct 8 00:40:51 EDT 2013


I'd like to see the dotted version vectors get launched, even with merging
siblings high concurrency = high amount of unnecessary siblings,
Which wastes space and impacts performance. Dotted version vectors helps
improve this. Proof of concept and paper available...
On Oct 7, 2013 3:06 PM, "Sam Elliott" <sam.elliott at basho.com> wrote:

> Each sibling has it's own last-modified date, which you should be able to
> use to sort them when you get them back.
>
> However, I'd suggest the following: if they're siblings, they were created
> from concurrent edits. Thus, create a merge function that is entirely
> deterministic without using the timestamp. This should save you from any
> clock skew issues, and also from the fact that an edit may not have been
> performed with the most up-to-date information.
>
> I guess people can't wait for our CRDTs to launch.
>
> Sam
>
> --
> Sam Elliott
> Engineer
> sam.elliott at basho.com
> --
>
>
> On Monday, 7 October 2013 at 2:47PM, Alex Rice wrote:
>
> > Yes, exactly that's what I'm working on. By knowing which sibling is
> > the oldest and which is the newest it seems like I can usually figure
> > out how to marge/apply the modifications. Things like Player profiles,
> > friends lists, etc.
> >
> > On Mon, Oct 7, 2013 at 12:43 PM, Jeremiah Peschka
> > <jeremiah.peschka at gmail.com (mailto:jeremiah.peschka at gmail.com)> wrote:
> > > There's no guarantee of return order as far as I know. Since you can't
> count
> > > on clocks anyway...
> > >
> > > Are you trying to determine which data modifications to apply from
> multiple
> > > siblings?
> > >
> > > ---
> > > sent from a tiny portion of the hive mind...
> > > in this case, a phone
> > >
> > > On Oct 7, 2013 11:40 AM, "Alex Rice" <alex at mindlube.com (mailto:
> alex at mindlube.com)> wrote:
> > > >
> > > > Are they ordered by timestamp, and is the ordering guaranteed?
> (within
> > > > the clock accuracy of course). Using the C# client Thanks,
> > > > Alex
> > > >
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